You will need to use the text book for this problem set. If you do not have access to a copy, you can use the online google book version which you can find through Mirlyn or via this link
The Parallel axis theorem is used to find the moment of inertia at a different point of rotation.

where
is equal to the mass of the object in kg and
is equal to the perpendicular distance between the CoM and new point of rotation.
The table you will use for this problem set (table 2.6) gives the moment of inertia about the CoM of the segments. The somersault axis represents the transverse axis and is the axis of interest for problem 6.
In problem 5, the coefficient of drag is given as
this is not correct, the coefficient does not have units (
)
The production of work based on oxygen consumption is


I highly recommend putting in your units when solving problem 5.
In table 2.5, you are given an average segment length for men and women (in cm), but a segment weight as a percentage of the subject's body weight and the location of the CoM as a percentage of segment length.
In problem 6c, you need to find the angle between the muscle and the arm in order to calculate the moment arm of the muscle (I recommend using a diagram to find the angle).










) then


is a function of angular velocity
and the distance from the center of rotation 
represents the change in magnitude of
and
accounts for the change in direction of 

and






and
in terms of 






(we need to find a theta which will maximize horizontal displacement!).
can vary between values of -1 to values of 1.


since you know the change in velocity and the time period, you can calculate a. Just be sure to use mass and not weight in the equation!

and
you only need to calculate
which will be equal and opposite to the centripetal force 


and since you know the horizontal force being applied to the horse by the gymnast, it is tempting to calculate the acceleration directly, however there is friction in play, and as long as the horizontal force applied by the gymnast does not overcome static friction, the horse will not move.

